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Simple Maths Puzzle
Difficulty Level

One guy had a habit of spending the money as per the day of the month, for example he will spend $18 on 18th of the month.
Once he spent, $63 in continuous 5 days, What could be the dates ?

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Lets assume all the days were of the same month, in that case
x + (x+1) + (x+2) + (x+3) + (x+4) = 63
5x = 53
x is coming out to be in decimal, which can not be. So the dates are not of the same month

Lets take the first case in which 4 dates are from one month and one date from next month
x + (x+1) + (x+2) + (x+3) + 1 = 63

4x = 56 => x = 14, but 1st cant come after 17th, so it is ruled out

Next case is 3 dates in one month and 2 in next month
x + (x+1) + (x+2) + 1 + 2 = 63
3x = 57 => x = 19, but again 1st cant come after 21, so it is ruled out as well

Now lets take 2 dates from one month and 3 dates from coming month.
x + (x+1) + 1 + 2 + 3 = 63
2x = 56 => x = 28, this is possible for the month with 29 days, i.e. February of leap year

So the continuous dates are
28th Feb
29th Feb
1st March
2nd March
3rd March

28+29+1+2+3 = $ 63

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