There were 200 Fishes in an aquarium

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There were 200 Fishes in an aquarium, 99% of which were red. How many red fishes must be removed to make the percentage of red fishes 98%?

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Number of red fish = 99% of 200 = 198

That means there are 198 red fishes in the aquarium and the 2 remaining fishes are of different colour.

Let the number of red fish removed be x.

198 - x = 98% of (200 - x)

198 - x = 98/100*(200 - x)

19800 - 100x = 19600 - 98x

19800 - 19600 = 100x - 98x

200 = 2x

x = 100

So 100 red fishes to be removed to make the percentage of red fishes 98%

100

Total all color fishes = 200 (100%) 99% of which were red = 200*99% = 198 fishesNow 100% of Red fishes is 198 And now calculate 98% of Red fishes = 198*98% = 194.04 So we need 4 Red fishes remove for get 98% of Red fishes 198-194 = 4Its my calculation Answer is = 4 Red fishes must removed for get 98% of Red fishes.

in simple way

Well, you start off with 200 fish. 99% of 200 fish would be: 200 x 0.99 = 198 red fish. Then, you want a total of 98% red fish remaining from your total of 200 fish. So, you want: 198 - f = 0.98(200 - f) 198 ? f = 196 ? 0.98f 0.02f = 2 f = 100 So, in order to have 98% of red fish remaining, you would need to remove 100 red fish.

100

Solve this one! ???????? ( 5 min Max )Q. There were 200 fishes in an aquarium, 99% of which were red. How many red fishes must be removed to make the percentage of red fishes 98%?Purely maths. ... No tricks. .....Ans: ______

100

100

by removing 100 fushes we can get 98% . 198-100/200-100 =0.98 0.98×100= 98%

100

in order to have 98% of red fish remaining, you would need to remove 100 red fish.

100

Answer is 100

Ans should be 2.