Holmes Puzzle: Price of Rings

Difficulty Level

Professor Morrison sold a total of three precious rings on the black market for $1,750. Holmes was able to trace all three rings and found that Morrison had sold off the second ring for $50 more than the first one, and the third ring for $600 less than the second one.

How much did Morrison receive for each ring?

View Answer Comments(4)

Answer: $750, $800, $200

Assume that the price of first ring was x

Price of 2nd ring was y

Price of 3rd ring was z

As given in the question, y = x+50

z = y-600 = (x+50)-600

This implies, x+y+z = $1,750

x+x+50+x+50-600 = 1,750

3x = 1750+600-100

x= 2250/3

x = $750

Hence, y =750+50=$800

z=800-600=$200

x+(x+5)+(x-600)

easier way is to find for the second ring first since both other rings price come from that.y+y-50+y-600=1750 3y-650=1750 3y=1750+650 3y=2400 y=2400/3 y=800 z=800-600=200 x=800-50=750

750 800 200

First ring-750 Second ring -800 Third ring-200