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Holmes Puzzle: Price of Rings
Difficulty Level

Professor Morrison sold a total of three precious rings on the black market for $1,750. Holmes was able to trace all three rings and found that Morrison had sold off the second ring for $50 more than the first one, and the third ring for $600 less than the second one.
How much did Morrison receive for each ring?

View Answer Comments(5)

Answer: $750, $800, $200

Assume that the price of first ring was x
Price of 2nd ring was y
Price of 3rd ring was z

As given in the question, y = x+50
z = y-600 = (x+50)-600
This implies, x+y+z = $1,750
x+x+50+x+50-600 = 1,750
3x = 1750+600-100
x= 2250/3
x = $750
Hence, y =750+50=$800
z=800-600=$200

Guest Said:Posted On 2017-05-15

like 7...i think.

Guest Said:Posted On 2016-12-17

x+(x+5)+(x-600)

Guest Said:Posted On 2016-10-30

easier way is to find for the second ring first since both other rings price come from that.y+y-50+y-600=1750 3y-650=1750 3y=1750+650 3y=2400 y=2400/3 y=800 z=800-600=200 x=800-50=750

Guest Said:Posted On 2016-07-23

750 800 200

Guest Said:Posted On 2016-07-17

First ring-750 Second ring -800 Third ring-200

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